f(2)=(2x+1)(2x^2-6)

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Solution for f(2)=(2x+1)(2x^2-6) equation: 


Simplifying
f(2) = (2x + 1)(2x2 + -6)

Reorder the terms for easier multiplication:
2f = (2x + 1)(2x2 + -6)

Reorder the terms:
2f = (1 + 2x)(2x2 + -6)

Reorder the terms:
2f = (1 + 2x)(-6 + 2x2)

Multiply (1 + 2x) * (-6 + 2x2)
2f = (1(-6 + 2x2) + 2x * (-6 + 2x2))
2f = ((-6 * 1 + 2x2 * 1) + 2x * (-6 + 2x2))
2f = ((-6 + 2x2) + 2x * (-6 + 2x2))
2f = (-6 + 2x2 + (-6 * 2x + 2x2 * 2x))
2f = (-6 + 2x2 + (-12x + 4x3))

Reorder the terms:
2f = (-6 + -12x + 2x2 + 4x3)
2f = (-6 + -12x + 2x2 + 4x3)

Solving
2f = -6 + -12x + 2x2 + 4x3

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by '2'.
f = -3 + -6x + x2 + 2x3

Simplifying
f = -3 + -6x + x2 + 2x3

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